4Al + 3O2 = 2Al2O3
a) How many moles of oxygen are required to react completely with 14.8 mol of Al? Please explain step by step.
b) How many moles of Al2O3 are formed when 0.78 moles of O2 reacts with Al? My answer: for each mole of O2 2/3 mole of Al2O3 is formed x=0.78*(2/3)=0.52 moles of Al2O3. Please correct and explain if it's wrong. Thank you a lot.
How many moles of oxygen?
a)4mol Al =3 02
1mol Al=3/4 02
14.8mol Al =3/4x14.8 mol 02= 11.1mole 02
b)3mol 02=2AL203
o.78mol 02=2/3x0.78mol AL2O3=0.52moles
here it is..ur answer is correct
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