How many moles of sodium phosphite are required to prepare 65.2 mL of 0.0822 M Na3PO3?

How many moles of sodium phosphite are required to prepare 65.2 mL of 0.0822 M Na3PO3?


A. 5.36 × 10^–3 moles Na3PO3





B. 7.93 × 10^–1 moles Na3PO3





C. 3.62 × 10^–2 moles Na3PO3





D. 8.22 × 10^–2 moles Na3PO3





E. 1.22 × 10^1 moles Na3PO3





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How many moles of sodium phosphite are required to prepare 65.2 mL of 0.0822 M Na3PO3?
65.2 mL * 0.0822 moles /L = 5.359 millimoles





So, A