If four moles of NH3 react to form two moles ofN2and six moles of H2, calculate Kp at the same temp?

In the gas phase one mole of N2 and three moles of H2 react to form two moles of NH3 At T = 298 Kelvin , Kp = 560000 atm-2





If four moles of NH3 react to form two moles of N2 and six moles of H2 , calculate Kp at the same temperture.

If four moles of NH3 react to form two moles ofN2and six moles of H2, calculate Kp at the same temp?
This is just the same reaction bacwards, but disguised a bit.


Simply take the inverse of the quoted Kp value.