Calculate the number of moles of potassium chlorate, KCLO3(s) that must decompose to produce potassium chloride, KCL(s) and 1.80 moles of oxygen gas.
Our teacher requires us to show work(step 0: balanced equation, 1: grams-moles, mole ratio and 3: moles: to grams so plz. include steps if you can. thanks
Calculate the number of moles of potassium chlorate, ....?
2KClO3(s) --%26gt; 2KCl(s) + 3O2(g)
divide the equation by the moles of the substance you are given as a know (O2)
2/3KClO3(s) --%26gt;2/3KCl + O2(s)
this says for every mole of O2 produced 2/3 mole of KClO3 was required
so if you have 1.8 moles O2
then you need ==%26gt; 1.8 * 2/3 moles KClO3 = 1.2 moles KClO3
Reply:The balanced equation is :
2 KClO3 %26gt;%26gt; 2 KCl + 3 O2
the ratio between KClO3 and O2 is 2 : 3
moles KClO3 needed = 1.80 x 2 / 3 = 1.20
camellia
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