How many moles of CaCN2 are needed to produce 20.0 moles of NH3?

Consider the ff. reaction:





CaCN2 + 3 H2O --------- CaCO3 + 2 NH3





which has a 50.0% yield. How many moles of CaCN2 are needed ot produce 20.0 moles of NH3?





molar mass for CaCN2 is 80.11 g/mol


molar mass for CaCO3 is 100.09 g/mol





Could you please show me an easy, step by step way to finish the problem, thank you.

How many moles of CaCN2 are needed to produce 20.0 moles of NH3?
CaCN2 +3H2O ------------ CaCO3 +2NH3


1________________________%26gt;2


20/2%26lt;_____________________20


in theory:


nCaCN2= 10 moles





in fact, n CaCN2=(10/50)*100=20 moles