How many moles of ions are present when .10 moles of the following compounds are dissolved in WATER?

How many moles of ions are present when .10 moles of the following compounds are dissolved in WATER?





A). K2SO4





B). Fe(NO3)3





C). Al2(SO4)3








D). NiSO4








Any help what so ever would be appreciated. Thanks!

How many moles of ions are present when .10 moles of the following compounds are dissolved in WATER?
a. 2k+ = .20moles , SO42-=.10moles





b.Fe3+=.10moles,3NO3-= .30moles





c.2Al3+=.20moles,3SO42-=.30moles





d. Ni2+=.10moles,SO42-=.10moles
Reply:Taking that what all of the salts form ions completely the following will happen





K2SO4 -%26gt; 2K+ + [SO4]2- = 3 ions so 3 x 0.1 = 0.3 moles


Fe(NO3)3 -%26gt; Fe3+ + 3[NO2]- = 4 ions so 4 x 0.1 = 0.4 moles


Al2(SO4)3 -%26gt; 2Al3+ + 3[SO4]2- = 5 ions so 5 x 0.1 = 0.5 moles


NiSO4 -%26gt; Ni2+ + [SO4]2- = 2 ions so 2 x 0.1 = 0.2 moles

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