Calculating the number of moles of each reactant?

When 111.7 g of iron and 212.7 g of chlorine gas completely react, iron(III) chloride, FeCl3, is formed. Calculate the number of moles of each reactant.





first, i made up and balanced the equation: 2 Fe + 3 Cl2 --%26gt; 2 FeCl3. To figure out the number of moles, I divided the molar masses into the masses that were given:


111.7 g Fe / 55.8 g Fe = 2.00 mol Fe, and


212.7 g Cl2 / 70.8 g Cl2 = 3.00 mol Cl2.





Is this correct? I don't think it is because the answers are the same as those in the balanced equation.





And once you find the number of moles, to get the amount of grams, you use the number of moles in the balanced equation and divide that into the moles you find from calculating, right?

Calculating the number of moles of each reactant?
It is correct. And your question about determining moles is also correct (yet not asked very clearly).


Don't doubt yourself so much. If the numbers all verify your answer, you are most likely right