How many moles of copper (II) nitrate are required to produce at least .50 moles of either N dioxide or O gas?

copper (II) nitrate decomposes upon heating to form copper (II) oxide, nitrogen dioxide gas, and oxygen gas. How many moles of copper (II) nitrate are required to produce at least .50 moles of either nitrogen dioxide or oxygen gas?








a. .50


b. 4.0


c. 2.0


d. .25


e. 1.0








show how you got it!

How many moles of copper (II) nitrate are required to produce at least .50 moles of either N dioxide or O gas?
First write equation:





Cu(NO3)2 --%26gt; NO2 + O2 + CuO





Balance Equation





2Cu(NO3)2 --%26gt; 4NO2 + O2 + 2CuO





From balanced Equation, O2 is limiting reagent.


So find amount of Cu(NO3)2 required to produce 0.5mol of O2 using dimensional analysis.





0.5mol O2 × 2 mol Cu(NO3)2 = 1 mol Cu(NO3)2 required. [E]


1 mol O2
Reply:2Cu(NO3)2 → 2CuO + 4NO2 + O2





2 mole of Cu(NO3)2 =%26gt; 2 mole of Cu, 4 moles of N, 12 moles of O





which would make 2xCuO+4xNO2+O2





the reason we have to take 2 moles in the beginning is to make sure we have O2 at the end.





So, it seems that the amount of O2 and the amount of NO2 are different at the end. if you want 0.5 moles of O2, you need 1 mole of Cu(NO2)3, if you yant 0.5 moles of NO2, you need 0.25 moles of Cu(NO2)3.





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