Saturday, April 24, 2010

How many moles of NaOH are required to neutralize 1.254x10^-3 moles of oxalic acid dihydrate?

How many moles of NaOH are required to neutralize 1.254x10^-3 moles of oxalic acid dihydrate?





oxalic acid dihydrate is diprotic

How many moles of NaOH are required to neutralize 1.254x10^-3 moles of oxalic acid dihydrate?
Since oxalic acid is diprotic, it will release 2 H+ for every molecule dissolved. NaOH only release one OH- for each molecule dissolved, so you need twice as much NaOH as oxalic acid.





(1.254x10^-3 mol oxalic acid) * 2 = 2.508*10^-3 mol NaOH
Reply:you need to write the balanced equation.





im too lazy to look up the chemical formula for oxalic acid... but you would only need then to mulitiply that given number by the ratio of NaOH to it to get the number of mole NaOH needed.


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