Given:
- Each mole of Fe(CN)6 (4-) loses exactly one mole of electrons in a reaction
- Once you know # of moles of electrons released, you know number of moles of electrons used to reduce...
- n(electrons) = n(Fe(CN)6 (4-))
- Moles after titrations I found were .0005 m, .000196 m
Does anyone know how I can find number of moles of electrons released? I have no idea where to start or what to consider to find the moles of electrons.
Thank you so much for your help :)
How do I calculate moles of electrons released?
You don't mention 0.0005 m or 0.0000196 m of what.
You treat the moles of electrons gained and lost the same as any atoms or ions in an equation. For example:
Na ===%26gt; Na+ + e- One mole of Na releases one mole of electrons.
Fe ===%26gt; Fe++ + 2e- Each mole of Fe releases two moles of electrons.
2F- ===%26gt; F2 + 2e- Every two moles of fluoride release two moles of electrons.
By the way, Fe(CN)6(41) ===%26gt; Fe(CN)6(3+) + e-
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