Stoichiometry and moles?

2 C4H10 + 13 O2 --%26gt; 8 CO2 + 10 H2O





...if 5 moles of C4H10 are used how many moles of water are produced...





if 10 moles of O2 are used how many moles of carbon dioxide are produced








how many grams of CO2 will be produced if 42 grams of C4H10 are used?

Stoichiometry and moles?
1. the value of C4H10 increased by 2.5 (5/2)


So multiply 10 moles of H2O by 2.5 = 25moles of H2O


Now this answer only applies if the 13 moles of oxygen were increased also by 2.5





If not the 10 moles of H2O will remain the same.





2. the value of O2 decreased by 0.769 (10/13)


So multiply 0.769 by 10 moles of H2O = 7.692





Again this answer only applies if the C4H10 decreased by 0.7692 as well!

lady slipper