Moles of particles in this reaction?

1. I have 0.4 moles of H2SO4


2. H2SO4 dissolves in water (so we have a solution)


3. 1st reaction (ionizes 100%)


H2SO4 --%26gt; H+ + HSO4-


4. 17.8% moles of HSO4- have this 2nd reaction


HSO4- --%26gt; H+ + SO4--





So with this information I need to know the moles of particles present in this reactions. According to me, there are 0.8712 moles of particles (of the first reaction 0.4 H+ plus 0.3288 HSO4-) (of the second reaction 0.0712 H+ plus 0.0712 SO4--) But I would like to know if you get the same results. Thanks for your answer. Win 10 points! =)

Moles of particles in this reaction?
From the reaction


H2SO4 %26gt;%26gt;H+ +H SO4- we will have 0.4 moles H+ and 0.4 moles HSO4- %26gt;%26gt;0.8





From the second reaction will react 17.8% of 0.4 %26gt;%26gt;0.0712


0.4-0.0712=0.328 HSO4- will not react


0.0712 HSO4- will produce 0.0712 H+ and 0.0712 SO42-





Total=0.8 + 0.328+0.0712+0.0712=1.27