Monday, November 16, 2009

How do I calculate moles of electrons released?

Given:


- Each mole of Fe(CN)6 (4-) loses exactly one mole of electrons in a reaction


- Once you know # of moles of electrons released, you know number of moles of electrons used to reduce...


- n(electrons) = n(Fe(CN)6 (4-))


- Moles after titrations I found were .0005 m, .000196 m





Does anyone know how I can find number of moles of electrons released? I have no idea where to start or what to consider to find the moles of electrons.





Thank you so much for your help :)

How do I calculate moles of electrons released?
You don't mention 0.0005 m or 0.0000196 m of what.





You treat the moles of electrons gained and lost the same as any atoms or ions in an equation. For example:





Na ===%26gt; Na+ + e- One mole of Na releases one mole of electrons.





Fe ===%26gt; Fe++ + 2e- Each mole of Fe releases two moles of electrons.





2F- ===%26gt; F2 + 2e- Every two moles of fluoride release two moles of electrons.





By the way, Fe(CN)6(41) ===%26gt; Fe(CN)6(3+) + e-


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