How many moles of oxygen are required to burn 34.2 g of methyl alcohol?

The methyl alcohol, CH3OH(l), used in alcohol burners combines with oxygen gas to form carbon dioxide and water.


How many moles of oxygen are required to burn 34.2 g of methyl alcohol?





Our teacher requires us to show work(step 0: balanced equation, 1: grams-moles, 2: mole ratio and 3: moles: to grams so plz. include steps if you can. thanks

How many moles of oxygen are required to burn 34.2 g of methyl alcohol?
0: balanced equation:


2CH3OH + 3O2 ==%26gt; 2CO2 + 4H2O





1: grams-moles:


Molar mass of CH3OH: 32.04 g/mol.





2: mole ratio:


2 moles of CH3OH need 3 moles of O2 to burn.





3: CH3OH moles:


(34.2g)/(32.04 g/mol) = 1.07 mol





4. Final:


(1.07mol)*3/2 = 1.60 mol (of O2 needed)