In the gas phase one mole of N2 and three moles of H2 react to form two moles of NH3 ....?

In the gas phase one mole of N2 and three moles of H2 react to form two moles of NH3 At T = 773 Kelvin , Kp = 0.000067 atm-2








If two moles of N2 and six moles of H2 react to form four moles of NH3 , calculate Kp at the same temperture.

In the gas phase one mole of N2 and three moles of H2 react to form two moles of NH3 ....?
Since the moles are doubled, then this translates to the squaring of concentrations when finding the Kp. Since the first Kp is given, and the second Kp has doubled its concentrations, you square the Kp of the first reaction.


Kp = (6.7 x 10^-5)^2 = 44.89 x 10^-10

grappling